show that (2x+3y)(2x-3y)+(3y-4z)(3y+4z)+(4z-2x)(4z+2x)=0
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{2x(2x-3y)+3y(2x+3y)}+{3y(3y+4z)-4z(3y+4z)}+{4z(4z+2x)-2x(4z+2x)}=0
(4x^2-6xy+6xy-9y^2)+(9y^2+12yz-12yz-16z^2)+(16z^2+8xz-8xz-4x^2)=0
4x^2-6xy+6xy-9y^2+9y^2+12tz-12yz-16z^2+16z^2+8xz-8xz-4x^2=0
Subtract the all LHS.
your answer is 0=0 hope it's helpful
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Answer:
{2x(2x-3y)+3y(2x+3y)}+{3y(3y+4z)-4z(3y+4z)}+{4z(4z+2x)-2x(4z+2x)}=0
(4x^2-6xy+6xy-9y^2)+(9y^2+12yz-12yz-16z^2)+(16z^2+8xz-8xz-4x^2)=0
4x^2-6xy+6xy-9y^2+9y^2+12tz-12yz-16z^2+16z^2+8xz-8xz-4x^2=0
Subtract the all LHS.
your answer is 0=0
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