show that. (2x+7)^2 - 56x =(2x-7)^2
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Answer:
= 0
Step-by-step explanation:
(2x+7)^2-56x=(2x-7)^2
2x whole square +7^2+2(2x)(7)-56x=(2x)^2+7^2-2(2x)(7)
4xsquare+49+28x-56x=4xsquare+49-28x
4xsquare-28x+49=4xsquare-28x+49
=0
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