Show that 2x + 7 is a factor of 2x3 + 7x2 – 14x – 14. Hence, factorise 2x2 + 7x2 – 4x – 14.
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Let p(x) = 2x³+7x²-4x-14
To show 2x+7 is a factor ,
Take , 2x + 7 = 0
2x = -7
=> x = -7/2
put x = -7/2 in p(x )
i ) p(-7/2 ) = 2(-7/2)³+7(-7/2)²-4(-7/2)-14
= -343/4 + 343/4 + 14 - 14
= 0
Therefore ,
2x + 7 is a factor of p(x).
[ By factor theorem ]
Now,
2x+7)2x³+7x²-4x-14(x²-2
2x³+7x²
p(x) = (2x+7)( x²-2 )
= (2x+7)[ x² - (√2)²]
= ( 2x + 7 )( x + √2 )( x - √2 )
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