Question

show that 2y2 - 8y - 3=0

Answer 1

2y² - 8y - 3 =0
Using the quadratic formula, u get,
y = 8+,-(plus or minus) √88
             4
Then, y = (8+√88)    and, y = (8-√88)                   
                4                            4
Therefore, y = 4.34 and -0.34
Hope this will help you.

Answer 2

2y²-8y-3=0
a=2
b=-8
c=-3

y=[tex] \frac{-b+- \sqrt{b^{2} -4ac} }{2a} \\ \\ y= \frac{8+- \sqrt{64 -4*2*-3} }{4} \\ \\ y= \frac{8+- \sqrt{64 +24} }{4} \\ \\ y=\frac{8+- 9.38 }{4} \\ \\ y=4.345 /or/ y=−0.345[/tex]