Question

show that (3,0) ,(6,4) , (-1,3) are the vertices of a right angle triangle .
.
.
.
plz answer correctly
.
.
.
this is 3 marks questions.
​​

Answer 1

Answer:

Question

❇️show that (3,0) ,(6,4) , (-1,3) are the vertices of a right angle triangle .

Solution ⬇️

✍️Consider A=(3,0) , B=(6,4) and C(-1,3)

<<---------------------------------------------------->>

✍️Taking A(3,0) and B(6,4)

✍️x1=3,x2=6,y1=0,y2=4.. given

______________________________

✍️By distance formula

✍️d(AB)=√(x2-x1)²+(y2-y1)²

✍️d(AB)=√(6-3)²+(4-0)²

✍️d(AB)=√(3)²+(4)²

✍️d(AB)=√9+16

✍️d(AB)=√25

_____________________________

✍️ Taking B(6,4) and C(-1,3)

✍️x1=6,x2=-1,y1=4,y2=3..(given)

_____________________________

✍️By distance formula

✍️d(BC)=√(x2-x1)²+(y2-y1)²

✍️d(BC)=√(-1-6)²+(3-4)²

✍️d(BC)=√(-7)²+(1)²

✍️d(BC)=√49+1

✍️d(BC)=√50

_____________________________

✍️ Taking A(3,0) and C(-1,3)

✍️x1=3,x2=-1,y1=0,y2=3..(given)

_____________________________

✍️By distance formula

✍️d(AC)=√(x2-x1)²+(y2-y1)²

✍️d(AC)=√(-1-3)²+(3-0)²

✍️d(AC)=√(-4)²+(3)²

✍️d(AC)=√16+9

✍️d(AC)=√25

___________________________

==>️d(BC)=d(AB)+d(AC)

==>️√50=√25+√25

==>️√50=√50

___________________________

❇️ Therefore proved

️A=(3,0) , B=(6,4) and C(-1,3) are right angled triangle

Step-by-step explanation:

hope you appreciate this ans