Show that (3,0) ,(6,4) ,(-1,3) are the vertices of a right angled triangle
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Step-by-step explanation:
A(3,0) , B(6,4) , C(-1,3)
AB = √(3-6)² + (0-4)² = √9+16 = √25 = 5
AC = √(3+1)² + (0-3)² = √16+9 = √25 = 5
BC = √(6+1)² + (4-3)² = √49+1 = √50 = 5√2
So BC² = AB² + AC²
Hence by Pythagoras theorem , triangle is right angled triangle.
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