Show that(3+√2)(3-√2)is not an irrational numbers
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Hey
→ ( a + b )( a - b ) = ( a² - b² )
Putting a = 3, b = √2,
→ ( 3 + √2 )( 3 - √2 ) = ( 3² - √2² ) = ( 9 - 2 ) = 7
=> The number '7' is rationale and hence is : ( 3 + √2 )( 3 - √2 )
→ ( a + b )( a - b ) = ( a² - b² )
Putting a = 3, b = √2,
→ ( 3 + √2 )( 3 - √2 ) = ( 3² - √2² ) = ( 9 - 2 ) = 7
=> The number '7' is rationale and hence is : ( 3 + √2 )( 3 - √2 )
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this is ur required result
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