Show that 3 + 2 √3 is an irrational number, where √3 is given to be irrational number. *
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let us assume on the contrary that 3+2√3 is rational. then there exists co prime positive integers a and b such that
3+2√3 = a/b
=> 2√3 = (a/b) - 3
=> √3 = (a - 3b)/2b
=> √3 is rational [ as a, b are integers, so,(a - 3b)/2b is a rational no.]
this contradicts the fact that √3 is irrational. so, our assumption is incorrect.
hence, 3+2√3 is an irrational number.
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