show that √3/2+5 is irrational
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Solution.
Let's assume that √3/2+5 is a rational number.
So, √3/2+5 = p/q , q≠0
=> √3/2 = p/q - 5
=> √3/2 = p-5q/q
=> √3 = 2(p-5q)/q
=> √3 = 2p - 10q / q
= integer/integer = a rational number.
Which contradicts the fact that √3 is an irrational number, so the above number is irrational.
Let's assume that √3/2+5 is a rational number.
So, √3/2+5 = p/q , q≠0
=> √3/2 = p/q - 5
=> √3/2 = p-5q/q
=> √3 = 2(p-5q)/q
=> √3 = 2p - 10q / q
= integer/integer = a rational number.
Which contradicts the fact that √3 is an irrational number, so the above number is irrational.
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