Question

Show that 3√2 is an irrational
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Answer 1

Answer:

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. ... So, it concludes that 3+√2 is irrational..

explanation:

prove :

prove :Let 3+√2 is an rational number.. such that 3+√/2 = a/b ,where a and b are integers and b is not equal to zero .. therefore,

prove :Let 3+√2 is an rational number.. such that 3+√/2 = a/b ,where a and b are integers and b is not equal to zero .. therefore,3 + √2 = a/b

prove :Let 3+√2 is an rational number.. such that 3+√/2 = a/b ,where a and b are integers and b is not equal to zero .. therefore,3 + √2 = a/b√2 = a/b -3

prove :Let 3+√2 is an rational number.. such that 3+√/2 = a/b ,where a and b are integers and b is not equal to zero .. therefore,3 + √2 = a/b√2 = a/b -3√2 = (3b-a) /b

prove :Let 3+√2 is an rational number.. such that 3+√/2 = a/b ,where a and b are integers and b is not equal to zero .. therefore,3 + √2 = a/b√2 = a/b -3√2 = (3b-a) /btherefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..

prove :Let 3+√2 is an rational number.. such that 3+√/2 = a/b ,where a and b are integers and b is not equal to zero .. therefore,3 + √2 = a/b√2 = a/b -3√2 = (3b-a) /btherefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..It means that √2 is rational....

prove :Let 3+√2 is an rational number.. such that 3+√/2 = a/b ,where a and b are integers and b is not equal to zero .. therefore,3 + √2 = a/b√2 = a/b -3√2 = (3b-a) /btherefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..It means that √2 is rational....But this contradicts the fact that √2 is irrational..

Answer 2

Answer:

3√2

=√2×9

=√18

the answer is √18