Math, asked by ali143T, 7 months ago

Show that 3 + √2 is an irrational number.

Answers

Answered by parthivkumarmusic
0

Answer:prove :

Let 3+√2 is an rational number.. such that

3+√2 = a/b ,where a and b are integers and b is not equal to zero ..

therefore,

3 + √2 = a/b

√2 = a/b -3

√2 = (3b-a) /b

therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..

It means that √2 is rational....

But this contradicts the fact that √2 is irrational..

So, it concludes that 3+√2 is irrational..

hence proved..

l hope it helped u..

thankyou

keep following...

BRAINLIEST PLZZZ

Step-by-step explanation:

Answered by hemadikshit3
0

Answer:

let 3+√2 is an rational numbers such that 3+√2=a/b where a and b are integers and b is not equal to zero,

therefore

3+√2=a/b

√2=a/b - 3

√2=(3b-a)/b

therefore

√2= (3b-a) /b is rational as a 3 is a integers it means that √2 is irrational

So 3+√2 is irrational number

hence it is proved

Step-by-step explanation:

sure it helps you

follow me

thank my answer

mark me as brainlist answer

Similar questions