Show that 3 + √2 is an irrational number.
Answers
Answer:prove :
Let 3+√2 is an rational number.. such that
3+√2 = a/b ,where a and b are integers and b is not equal to zero ..
therefore,
3 + √2 = a/b
√2 = a/b -3
√2 = (3b-a) /b
therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..
It means that √2 is rational....
But this contradicts the fact that √2 is irrational..
So, it concludes that 3+√2 is irrational..
hence proved..
l hope it helped u..
thankyou
keep following...
BRAINLIEST PLZZZ
Step-by-step explanation:
Answer:
let 3+√2 is an rational numbers such that 3+√2=a/b where a and b are integers and b is not equal to zero,
therefore
3+√2=a/b
√2=a/b - 3
√2=(3b-a)/b
therefore
√2= (3b-a) /b is rational as a 3 is a integers it means that √2 is irrational
So 3+√2 is irrational number
hence it is proved
Step-by-step explanation:
sure it helps you
follow me
thank my answer
mark me as brainlist answer