show that 3+√2 is irrational
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Let 3+√2 be a rational number
All rational numbers can be expressed in the form of p/q
So 3+√2=p/q
√2=p/q-3
√2=3q-p/q
As p,q are integers RHS is an irrational number
So LHS i.e √2 will be rational
But this contradicts the fact that √2 is irrational
This contradiction arise because of the false assumption. So 3+√2 is irrational
Hope it helps!!!
Let 3+√2 be a rational number
All rational numbers can be expressed in the form of p/q
So 3+√2=p/q
√2=p/q-3
√2=3q-p/q
As p,q are integers RHS is an irrational number
So LHS i.e √2 will be rational
But this contradicts the fact that √2 is irrational
This contradiction arise because of the false assumption. So 3+√2 is irrational
Hope it helps!!!
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