show that 3-√2 is irrational
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let us assume to the contrary that 3- ✓2 is a rational number then
3 - ✓2 = a/b.
where a and b are co-integers
✓2. = 3 - a/b
✓2 = 3b -a/b
as a and b are integers so it is a rational number so 3b-a/b is also a rational number so ✓2 is also rational number
but as we know ✓2 is irrational so our assumption was wrong and 3-✓2 is irrational
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