show that 3- √2 is irrational
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We know that √2is an irrational number.
Let us assume to the contrary that 3-√2 is a rational number.
so, 3-√2=a/b
√2=3-a/b
√2=(3b-a)/b
We know that (3b-a)/b is a rational number so √2is a rational number. This contradicts the fact that √2 is a rational number. This contradiction has arisen because of our wrong assumption that 3-√2 is a rational number so 3-√2 is an irrational number.
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