Question

Show that 3√2 is irrational​

Answer 1

Answer:

Step-by-step explanation:

Let us consider that 3root2 is a rational number. It can be written in the form p/q (p and q are co primes)

p/q = 3root2

p/3q = root2

Now,

p/3q = integer/interger

= rational number

But, this contradicts the fact that root2 is irrational.

Therefore, our assumption that 3root2 is rational is WRONG.

Hence, 3root2 is an irrational number.

Answer 2

Answer:

Yes.... It is an irrational number because it doesn't have perfect square root........

Verifying:- (3√2)^2......=9*2=18....

Hence, proved......

Please mark my answer as brainliest answer....