Question

show that 3 √2 is irrational ?
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Answer 1

Answer: prove :

Let 3+√2 is an rational number.. such that

3+√2 = a/b ,where a and b are integers and b is not equal to zero ..

therefore,

3 + √2 = a/b

√2 = a/b -3

√2 = (3b-a) /b

therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers..

It means that √2 is rational....

But this contradicts the fact that √2 is irrational..

So, it concludes that 3+√2 is irrational..

hence proved..

i hope this helps you

Answer 2

$3 \sqrt{2 } \\ 4.2426406871$

(3√2)this is not a prefect square