Question

show that 3√2 is irrational​

Answer 1

Step-by-step explanation:

Let us assume,

that 3√2 is irrational.

That is, we can find coprime a and b (b not equal to 0) such that 3√2=a/b.

Rearranging, we get

√2=a/3b

Since, a and b are integers,

a/3b is irrational, and so √2 is irrational.

But this contradicts the fact that √2 is irrational.

So, we conclude that 3√2 is irrational.

Our Assumption is wrong.

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