Show that 3√ 2 is irrational
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the decimal expansion of 3√2 is non-terminating and non-recurring so it is irrational
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Answer:
Let us assume to the contrary that 3√2 is rational
there fore
3√2 = a/b
√2 = a/3b
√2 is a rational [ 3, a and b are integers , a/3b is a rational number ]
This contradict the fact that √2 is irrational
Hence 3√2 is an irrational number
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