show that (√3-√2) is irrational
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Step-by-step explanation:
given: (√3-√2)
R.T.P:let us assume the that (√3-√2) is rational
it can be written in p / q form or a / b form where A and B are co prime
proof: (sobs) squaring on both sides , we get
after squaribg roots get cancel
2 + 3 - 2√6 = (a2/b2)
So,5 - 2√6 = (a2/b2) a rational no.
So, 2√6 = 5- (a2/b2)
Since, 2√6 is an irrational no. and 5 - (a2/b2) is a rational no.
So, my contradiction is wrong.
so our assumtion is wrong
So, (√3 - √2) is an irrational no.
LHS is not = to RHS
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