Show that√3+ 4 is an irrational number.
read the question carefully there is root in only 3 not in 4.
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let assume √3+4 is rational number
√3+4=r where r is rational
squaring both the side
(√3+4)²=r²
(√3)²+4²+8√3=r²
3+16+8√3=r²
8√3=r²-19
√3=(r²-19)/8
hence RHS is rational but LHS is irrational
this contradiction fact that our assumption is wrong
√3+4 is an irrational number.
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