show that (3,4) is equidistant from (1,7) and (5,1)
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Let (3,4) be A
And
(1,7) be B
And
(5,1) be C
Put the formula
AB=BC
First AB distance
Then
BC distance
Formula is Ab= under root (X1 - X2) +(Y1-Y2)
And
(1,7) be B
And
(5,1) be C
Put the formula
AB=BC
First AB distance
Then
BC distance
Formula is Ab= under root (X1 - X2) +(Y1-Y2)
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