Question

show that 3ⁿ ×4m can't end with the digit 0 or 5 for any natural numbers 'n' & 'm'

Answer 1

Answer:

We know that if a number should end with zero, it's prime factorisation should be 2×5(at least once)

Here,

3n=(1×3)n ≠2×5

and, 4m=(2×2)m is also≠ 2×5

Therefore we can conclude that,

3n×4m=12nm cannot end with zero or five.

HOPE IT HELPS....