Question

show that (√3+√5)^2 is an irrational number

Answer 1

(root3+root5)^2
firstly open the brackets because we should not add root 3 in root 5
(root 3+ root 5) ×(root 3 ×root 5)
now multiply the brackets
root3×root3 + root3×root 5+root5 × root 3 + root5 × root 5
3+ root 15+root15+ 5
3+ 2root15 + 5
8 + 2root 15
hope it will help u

Answer 2

while expanding the given term by using the formula of the (a+b)²= a²+b²+2ab
we have
a=√3
b=√5
we have 8+2√15
which is clearly a irrational number containing √15