show that √3 +
5
√3
is irrational.
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Answer:
let root 3 + roof 5 be rational
root 3 + root 5 = P/q
(root 3 + root 5) sq=(P/q)sq
3 +5 + 2 root 15 = P sq/q Sq
root I5 = (Psq / qsq -7) 1/2
RHS is rational as all are integers
⇒ LHS is also rational but root 15 is irrational
⇒ root3 + root 5 is irrational
Step-by-step explanation:
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