show that √3+√5 is an
irration3+
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let us assume that root 3 + root 5 is rational and its core Prime are p and q .
root 3 +root 5=p/q
root 5=p/q-root 3
(root 5)^2=(p/q-root3)^2 (squaring both side)
5=P^2/q^2-2p root 3/q+3
2p root3/q=p^2/q^2+3-5
2p root3/q=p^2/q^2-2q^2
root3=p^2/q^2-2q^2×q/2p
root 3= p^2 -2q^2/2pq
since root 3 is an irrational number,but p^2-2q^2/2pq is an rational number ,which is contradicts, so,our assumption is wrong ,hence (root 3+root 5) is an irrational number.
Hope it will help you...
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