Question

show that 3√5 is an irrational number. ​

Answer 1

Your answer is here ☺️☺️

Let us assume that 3− √5

is a rational number

Then. there exist coprime integers p, q,q



=0 such that

3− √5 p/q

=>5

=3− p/q

Here, 3− p/q

is a rational number, but 5 is a irrational number.

But, a irrational cannot be equal to a rational number.

This is a contradiction.

Thus, our assumption is wrong.

Therefore 3− 5 is an irrational number.

Hope it helps you✌️✌️