Question

Show that 3 - √5 is irrational.

Answer 1

Let us assume that 3 - $\sqrt{5}$ is rational.
 Then it can be written in the form p/q, were p and q are integers and q $\neq$ o.
 
i.e., 3 - $\sqrt{5}$ = p/q
 
then - $\sqrt{5}$ = p - 3q / q

here the R.H.S is rational , but L.H.S is irrational.
This is a contradiction. Thus our assumption is wrong.
 3 - $\sqrt{5}$ is irrational.

Answer 2

Step-by-step explanation:

hope it helps...........