show that 3 + 7 root 2 is an irrational number ..
is the sum of two irrational number always irrational...
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Answered by
11
s sum of two irrational no. is always irrational.
take an example of underroot 2 and underroot 2 there sum comes out to be 2underoot 2
Assume thus no. To be rational no. shift 2 on RHS underroot 2 is irrational no.but p/2q is irrational no. and write the solution which I wrote in pic
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take an example of underroot 2 and underroot 2 there sum comes out to be 2underoot 2
Assume thus no. To be rational no. shift 2 on RHS underroot 2 is irrational no.but p/2q is irrational no. and write the solution which I wrote in pic
hope this answer is helpful plz mark it as brainliest.
if u think I can help u just follow.
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radhika mark it as brainliest
Answered by
10
Answer:
Let us assume 3+7 √2 as rational number
3+7√2 =a\b
√2 = a/7b - 3
Here,
a/7b -3 is rational number so
3+7√2 is also rational number
But √2 is irrational
This contradiction had arrisen due to our incorrect assumption
This contradicts the fact that 3+7√2 is irrational
Hope it helps u ☺☺
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