Question

Show that 3 & -1/2 are the roots of the quadratic equation 2x²-5x-3=0

Answer 1

step by step explanation

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Answer 2

Quadratic equation:

Step-by-step explanation:

$\ Given \ equation: \\\\2x^2-5x-3=0 \\\\\ points: \\\\3, - \frac{1}{2}\\\\\ Solution:\\\\\ put \ the \ given \ points \ in \ given \ equation: \\\\ 2x^2-5x-3=0 \\\\x= 3 \\\\\rightarrow 2(3)^2-5(3)-3=0 \\\\\rightarrow 2(9)-5(3)-3=0 \\\\\rightarrow 18-15-3=0 \\\\\rightarrow 0=0 \\\\ x= -\frac{1}{2} \\\\\rightarrow 2(-\frac{1}{2})^2-5(-\frac{1}{2})-3=0 \\\\\rightarrow 2\times\frac{1}{4}+5\times\frac{1}{2}-3=0 \\\\\rightarrow \frac{1}{2}+5\times\frac{1}{2}-3=0$

$\rightarrow \frac{1}{2}+\frac{5}{2}-3=0 \\\\\rightarrow \frac{1+5-6}{2}=0 \\\\\rightarrow \frac{6-6}{2}=0 \\\\\rightarrow \ 0=0$

So, the given point is a part of quadratic equation.

Learn more:

• quadratic equation: https://brainly.in/question/12556251