show that√3 is not a ratioal number
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let's root √3 be a rational number.
now √3=a/b (because a rational number can be written in the form of a /b.)
now,
√3=a/b
squaring both sides
3 = a^2/b^2
a^2=3b^2
now 3 is a factor of a square
also 3 is a factor of a.
let's a equal to 3 c.
then equation one can be written as-
3b^2=(3c)^2
3 is a factor of b square
also 3 is a factor of B.
no we see that 3 is a factor of a and b both so it contradicts our supposition that root 3 is rational.
so root 3 is a irrational number...
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