Question

Show that 3 power m and 4 power n
cannot ends with 0 or5 for any natural number n and m

Answer 1

Answer:

Step-by-step explanation:

3^1 = 3

3^2= 9

3^3 = 27

3^4 = 81

3^5 = 243

we see that after fourth power, the unit digit start to repeat, therefore only unit digit possible= 3, 9, 7, 1

similarly

4^1 =4

4^2=16

4^3=64

4^4=256

4^5=1024

we see that after second power, the unit digit start to repeat, therefore only unit digit possible= 4, 6

THEREFORE THEY CAN NEVER HAVE 0 OR 5

CHEERS MATE

PLEASE DO MARK BRAINLIEST