show that 3 root 2 is an irrational number
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prove:
Let 3+√2 is an rational number …such that
3+√2=a/b,where a and b are integers
and b is not equal to zero…
therefore
3+√2=a/b
√2=a/b-3
√2=(3b-a)/b
therefore,√2=(3b-a)/b is a rational number as,
b and 3 are integers…
It means that √2 is rational…
BUT IT CONDIRACTS THE FACT THAT √2 is irrerational…
SO IT CONDUCTS THAT 3+√2 is irrerational , hence it is proved…
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