Question

Show that 3 - root 2 is an irrational number

Answer 1

Answer:

3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. But this contradicts the fact that √2 is irrational.. So, it concludes that 3+√2 is irrational..

Step-by-step explanation:

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Answer 2

Answer:

hence,3-√2= a/ b , where a and b are integers and b is not equal to 0... therefore , the contradiction we suppose is wrong , hence, 3-√2 is irrational number ...