Show that 3 *root 3 is an irrational number
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Step-by-step explanation:
Let us assume that 3√3 is rational
Therefore, 3√3 =a/b, where a and b are co prime and b≠ 0.
√3=a/b*1/3
LCM=3b.
√3=3a/3b*b/3b
As a, b and 3 are integers, 3a/3b*b/3b is rational.
Therefore√3 is rational as LHS=RHS.
But it is given √3 is irrational.
Hence our assumption is wrong that √3/3 is rational.
Therefore √3/3 is rational.
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