Show that 3 + root2 is an irrational number.
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3+√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. But this contradicts the fact that √2 is irrational.. So, it concludes that 3+√2 is irrational..
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Answer:
Let us consider that 3 root 2 is a rational. It can be written in the form p/q(p and q are co - primes)
p/q = 3 root 2
p/3q = root2
Now,
p/3q = integer / integer = rational number
But this contradicts the fact that root 2 is an Irrational number.
There fore, our assumption that 3 root 2 is a rational number is wrong.
Hence, 3 root 2 is an Irrational number
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