Show that 3 root7s an irrational number
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let assume it's rational
so
3√7=a/b
√7=a/3b
but √7 is irrational
so our assumption contradicts.
so 3√7 is irrational
so
3√7=a/b
√7=a/3b
but √7 is irrational
so our assumption contradicts.
so 3√7 is irrational
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