Question

show that:
3 Sin 17° Sec 73° + 2 Tan 20° Tan 70°= 5.​

Answer 1

Answer:

3Cos73deg * sec73deg + 2tan20deg * cot20deg (complementary angles: sin(90-theta)=cos theta & tan(90-theta)=cot theta)

3*cos73deg*1/cos73deg + 2tan20deg*1/tan20deg(sec theta=1/cos theta & cot theta=1/tan theta)

3+2=5(as like terms will get cancelled)

Hence proved(LHS=RHS)

hope this helps

Step-by-step explanation:

Answer 2

Answer:

Hello mate!

Here is your answer.. Kindly check the above picture for your answer..

Hope it helps you..