Question

show that 3
$\sqrt{2 is \: irrational \:with \: process$
​

Answer 1

SRRY CAN 'T UNDERSTAND THE QUESTION srry

Answer 2

Answer:

Let us assume, to the contrary, that 3

2

is

rational. Then, there exist co-prime positive integers a and b such that

3

2

=

b

a

⇒

2

=

3b

a

⇒

2

is rational ...[∵3,a and b are integers∴

3b

a

is a rational number]

This contradicts the fact that

2

is irrational.

So, our assumption is not correct.

Hence, 3

2

is an irrational number

Step-by-step explanation:

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