Math, asked by rajyalakshmithota100, 6 months ago

Show that 3" x 4" cannot end with the digit 0 or 5 for any natural numbers
n'and 'm'
EXERCISE - 1.2
1. Express each of the following number as a product of its prime factors.
(i) 140 (ii) 156
(iii) 3825 (iv) 5005 (v) 7429
. Find the LCM and HCF of the following integers by the prime factorization me
(i) 12, 15 and 21 (ii) 17, 23, and 29 (iii) 8, 9 and 25
(iv) 72 and 108 (v) 306 and 657
Check whether 6" can end with the digit 0 for any natural number n.
Explain why 7 x 11 x 13+13 and 7 x 6 x 5 x 4 x 3 x 2 x 1 +5 an
numbers.​

Answers

Answered by kamanasrivastava1996
1

Answer:

to end with digit 0 and 5 ,it is required that no.should be a factor of 5.

But here,for any natural no. n and m.It is not possible.

Answered by djrockey2006
0

ITS NOT POSSIBLE. PLZ EXPLAIN WHAT YOUR QUESTION IS.

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