Question

Show that(3a-2b)(3a+2b)+(2a-3b)(2a+(3b)=13(a+b)(a-b)​

Answer 1

Answer:

hope it helps you!!!!!!

Answer 2

Step-by-step explanation:

(3a-2b)(3a+2b)+(2a-3b)(2a+3b) = 13(a+b)(a-b)

(3a)^2-(2b)^2 + (2a)^2-(3b)^2 = 13 (a^2 -b^2) [ x^2-y^2=

9a^2 - 4b^2 + 4a^2 - 9b^2 = 13 (a^2 - b^2). ( x-y)(x+y)]

13a^2 - 13 b^2 = 13a^2 - 13b^2

LHS = RHS

Hence Proved