Question

Show that 3n×4m cannot end with the digit 0 and 5 for any natural number n and m

Answer 1

Answer:

Step-by-step explanation:

Yes by fundamental theorem of arithematic in class10 chapter 1

Answer 2

Answer:

let n=6 & m=9

so

3 (6)×4 (9)

18×36

=648

in which end digit not equel to 0&5