Show that 3n×4m cannot end with the digit 0 or 5 for any natural numbers n and m
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if n and m are equal to 1 3n×4m Is equal to 12
if 2 the product formed is 48 and so on for any natural number thus 3n×4m cannot end with 0 or 5
if 2 the product formed is 48 and so on for any natural number thus 3n×4m cannot end with 0 or 5
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