Question

show that 3ñ×4m cannot end with the digit 0 or 5 for any natural numbers ‘n' and ‘m'.​

Answer 1

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3n × 4m = 12mn

12 will only end with 0 if it will multiply with 5 or 0

Hence 3n × 4m cannot end with digit 0 or 5

Answer 2

Answer:

3n × 4m = 12mn

12 will only end with 0 if it will multiply with 5 or 0

Hence 3n × 4m cannot end with digit 0 or 5

Step-by-step explanation:

Hope it helps dear mark as brainliest please