show that 3ñ ×4m cannot end with the digit 0 or 5 for nay natural numbers n and m.
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Step-by-step explanation:
The prime factors of the number are 3 and 2.
If any number want to be end with zero it should have 2 and 5 as its prime factors.
The given number hasn't 5 as its prime factor. Hence it can not end with zero.
The given number want to be end with 5, it should 5 as its of prime factors. But 3n∗4m do not have 5 as a factor. Hence, it can not end with 5.
Answered by
1
Answer:
The given number want to be end with 5, it should 5 as its of prime factors. But 3n∗4m do not have 5 as a factor. Hence, it can not end with 5.
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