Math, asked by pandev30566, 4 months ago

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(3p-5q)^2 + 60pq =(3p+5q)^2

Answers

Answered by crushycandy
4

Answer:

given:

(3p-5q)²+60pq = (3p+5q)²

=> (3p)²-2(3p)(5q)+(5q)²+60pq = (3p)²+2(3p)(5q)+(5q)²

{(a-b)²= a²-2ab+b² }

{(a+b)²= a²+2ab+b²}

=> 9p²-30pq+25q²+60pq = 9p²+30pq+25q²

=> 9p²+30pq+25q² = 9p²+30pq+25q²

hence

LHS = RHS

Answered by bidyutdasgupta
0

(3p-5q)^2+60pq

9p^2-30pq+25q^2+60pq

9p^2+30pq+25q^2

(3p)^2+2×3p×5q+(5q)^2

(3p+5q)^2[proved]

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