show that 3root 5 -1 is not a rational number , means 3root 5-1 is irrational
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ak4715:
by contradiction
Answers
Answered by
1
let 3root5 be a/b
3root5=a/b
by squaring both side
45b^2=a^2...........eq1
now,let 3root5=b/c
by sqaring both side
45c^2=b^2............eq2
so ,in eq1 and eq2 Factors are same
and in rational nos. factors are not same
............ty
3root5=a/b
by squaring both side
45b^2=a^2...........eq1
now,let 3root5=b/c
by sqaring both side
45c^2=b^2............eq2
so ,in eq1 and eq2 Factors are same
and in rational nos. factors are not same
............ty
Answered by
2
Howdy !!
your answer is here ---
Let us suppose that 3√5-1 is a rational
so, 3√5-1 = a/b where a and b are integers and b is not equal to 0
=> 3√5 = a+b/b
=> √5 = a+b/3b
now, a+b/5b is a rational number [ since a and b are integer ]
so, √5 is also a rational no. [√5 = a+b/3b]
but this contradict the fact that √5 is irrational .
therefore, our assumption is wrong
hence , 3√5-1 is irrational ..
hope it help you
==========✌✌✌✌✌✌✌✌===========
your answer is here ---
Let us suppose that 3√5-1 is a rational
so, 3√5-1 = a/b where a and b are integers and b is not equal to 0
=> 3√5 = a+b/b
=> √5 = a+b/3b
now, a+b/5b is a rational number [ since a and b are integer ]
so, √5 is also a rational no. [√5 = a+b/3b]
but this contradict the fact that √5 is irrational .
therefore, our assumption is wrong
hence , 3√5-1 is irrational ..
hope it help you
==========✌✌✌✌✌✌✌✌===========
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