Question

show that 3root48-4root75+root192=0​

Answer 1

Answer:

yes answer is zero.

Step-by-step explanation:

12√3-20√3+8√3=0

Answer 2

Step-by-step explanation:

Given:

Given:3root48-4root75+root192=0

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192It can be written as:

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192It can be written as:3root(2×2×2×2×3)-4root(3×5×5)+root(2×2×2×2×2×2×3)

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192It can be written as:3root(2×2×2×2×3)-4root(3×5×5)+root(2×2×2×2×2×2×3)=12root3-20root3+8root3

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192It can be written as:3root(2×2×2×2×3)-4root(3×5×5)+root(2×2×2×2×2×2×3)=12root3-20root3+8root3= -8root3+8root3

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192It can be written as:3root(2×2×2×2×3)-4root(3×5×5)+root(2×2×2×2×2×2×3)=12root3-20root3+8root3= -8root3+8root3=0=R.H.S.

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192It can be written as:3root(2×2×2×2×3)-4root(3×5×5)+root(2×2×2×2×2×2×3)=12root3-20root3+8root3= -8root3+8root3=0=R.H.S.Hence,L.H.S=R.H.S

Given:3root48-4root75+root192=0Take L.H.S. as 3root48-4root75+root192It can be written as:3root(2×2×2×2×3)-4root(3×5×5)+root(2×2×2×2×2×2×3)=12root3-20root3+8root3= -8root3+8root3=0=R.H.S.Hence,L.H.S=R.H.SHence,proved