: Show that 3V2 is irrational.
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Answer:
Step-by-step explanation:
Let us assume that 3√2 is rational
ie,3√2=a/b
where a and b are co-prime numbers
√2=(a/b)(1/3)
=a/3b
Here √2 is irrational and a/3b is rational
Thus our assumption is wrong
hence 3√2 is irrational
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