Question

show that (3x)³+(2y)³= (3x+2y) (9x²-6xy+4y²)​

Answer 1

Step-by-step explanation:

$(3 {x})^{3} + (2 {y})^{3} \\( 3x + 2y)(3x)^{2} - 3x\times 2y + 4 {y}^{2} \\ (3x + 2y)(9 {x}^{2} - 6xy + 4 {y}^{2} )$

Answer 2

Step-by-step explanation:

3x^3 +2x^3

=(3x+2y)^3 - 3.3x.2y.(3x+2y)

=(3x+2y).{(3x+2y)^2 - 18xy}

=(3x+2y).(9x^2+12xy+4y^2-18xy)

=(3x+2y).(9x^2-6xy+4y^2)