Question

show that 3x-4y+5=0,7x-8y+5=0, 4x+5y-45=0 are concurrent
find point of concurrent​

Answer 1

Step-by-step explanation:

3x-4y+5=0

7x-8y+5=0

applying substitution method for finding X and y

3x-4y+5=0

(3x+5)÷4=y

7x-8y+5=0

$7x - 8(3x + 5) \div 4 + 5 = 0$

7x-(24x-40)÷4+5=0

28x_24x-40+20=0

4x-20=0

X=5

substitute it on equation 1

(3×5+5)÷4=y

y=5

(5,5)

by applying this points on eq 3

4x+5y-45=0

4×5 +5×5 -45=0

45-45=0

0=0 hence proved